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Find the equation of angle of bisector of two lines 3x+4y-3=0 12x-5y+3=0 & one is the acute bisector

Find the equation of angle of bisector of two lines 3x+4y-3=0 12x-5y+3=0 & one is the acute bisector
 

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear student
 
a1 * a2 + b1 * b2 = + ve
 
hence negative sign gives acute angle bisector.
3x + 4y -3 / 5 = – (12 x – 5y + 3) /13
 
now solve this

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