Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Find the equation of a circle which passes through the points (2, –2), and (3, 4) and whose centre lies on the line x + y = 2.

Grade:Upto college level

1 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
7 years ago
Hello student,
Please find the answer to your question below
Let the equation of a circle is
x2+y2+2gx+2fy+c=0
Given it passes through (2,-2) and (3,4)
Hence by substituting the pts in equation of circle we get
4g-4f+c=-8.....(1)
6g+8f+c=-25.....(2)
subtracting 1 from 2 we get
-2g-12f=17..........(3)
also given center lies on x+y=2
So -g-f=2..........(4)
solving 3,4 we get g=-7/10,f=-13/10 and c=-104/10
By substituting above values in circle equation we get
The equation of a circle which passes through the points (2, –2), and (3, 4) and whose centre lies on the line x + y = 2 is
10x2+10y2-14x-26y-104=0

ASK QUESTION

Get your questions answered by the expert for free