Find the eccentric angle of the point (x 1 ,y 1 ) on the ellipse x 2 /6 + y 2 /2=1 whose distance from the centre is 2.

Question

Rahul Thakur · Answer

let the eccentric angle be t ; a 2 = 6 ; b 2 = 2 x 1= acost x 2 = asint (acost) 2 + (bsint) 2 =4 t = +45 ; −45

Shubhranshu Pattnaik · Answer

Let t be the eccentric angle , a 2 =6 , b 2 =2 and point p(acost,asint). It’s given distance of point from center(0,0) is 2 so by using distance formula, (acost) 2 +(bsint) 2 =4 On solving we get : cos 2 t=1/2 So t= 45

ankit singh · Answer

We know, 6 Π ​ + θ = π ⇒ θ = 6 5 π ​ in an ticlockwise direction So, eccentric angle is − 6 5 π thank u regards ankit singh manit bhopl ​

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Find the eccentric angle of the point (x 1 ,y 1 ) on the ellipse x 2 /6 + y 2 /2=1 whose distance from the centre is 2.

Find the eccentric angle of the point (x₁,y₁) on the ellipse x²/6 + y²/2=1 whose distance from the centre is 2.

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Find the eccentric angle of the point (x 1 ,y 1 ) on the ellipse x 2 /6 + y 2 /2=1 whose distance from the centre is 2.

Find the eccentric angle of the point (x1,y1) on the ellipse x2/6 + y2/2=1 whose distance from the centre is 2.

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Find the eccentric angle of the point (x₁,y₁) on the ellipse x²/6 + y²/2=1 whose distance from the centre is 2.