Samyak Jain
Last Activity: 7 Years ago
f(x) = log
10 ( [cosx] – [sinx] )
–1/2 = log
10 (1/
[cosx] – [sinx] )
For domain of f(x) number & base of logarithm should be positive.
1/
[cosx] – [sinx]
0 i.e. [cosx] – [sinx]
0 …...............(1)
But denominator of 1/
[cosx] – [sinx] cannot be zero.
i.e. [cosx] – [sinx]
0 ….....................(2)
From (1) & (2), [cosx] – [sinx] > 0
Study graphs of [cosx] & [sinx] to get x
[(3
/2) + 2k
, (2
) + 2k
] ,
k
Integers.
Domain of f(x) is [(3/2) + 2k , (2) + 2k] , k Integers.
