Grade 12Algebra
find the coordinates of the foot of the perpendicular from (-2.5) to 3x+y+11=0
find the coordinates of the foot of the perpendicular from (-2.5) to 3x+y+11=0
2 Answers
Arun
for foot of perpendicular
(x + 2)/ 3 = (y – 5)/ 1 = – ( – 6 + 5 + 11)/ (9 + 1)
now use this and you will find x and y which are the foot of perpendicular
Samyak Jain
Method 1 : Given equation : 3x + y + 11 = 0 …..........(1)
Slope = – 3
Slope of line perpendicular to given line = –1/ –3 = 1/3
y – 5 = (1/3)(x + 2) i.e. x – 3y + 17 = 0 ...............(2)
Point of intersection of lines given by (1) & (2) is (– 5,4) .
Method 2 : Parametric form.
Foot of perpendicular from (x1 , y1) to ax + by + c = 0 can be found by formula
(x – x1) / a = (y – y1) / b = (ax1 + by1 + c) / a2 + b2
Solving, we get x = – 5 , y = 4
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