0

Guest

Courses New

find the coordinates of the foot of the perpendicular from (-2.5) to 3x+y+11=0

find the coordinates of the foot of the perpendicular from (-2.5) to 3x+y+11=0

Grade:12

2 Answers

Arun
25750 Points
5 years ago
for foot of perpendicular
 
(x + 2)/ 3 =  (y – 5)/ 1 =  – ( – 6 + 5 + 11)/ (9 + 1)
 
now use this and you will find x and y which are the foot of perpendicular
Samyak Jain
333 Points
5 years ago
Method 1 : Given equation : 3x + y + 11 = 0                …..........(1)
Slope = – 3
Slope of line perpendicular to given line = –1/ –3 = 1/3
\therefore Equation of perpendicular line from (-2.5) to 3x+y+11=0 is
y – 5 = (1/3)(x + 2)   i.e. x – 3y + 17 = 0                      ...............(2)
Point of intersection of lines given by (1) & (2) is (– 5,4) . 
Method 2 : Parametric form.
Foot of perpendicular from (x1 , y1) to ax + by + c = 0 can be found by formula 
(x – x1) / a  =  (y – y1) / b  =  (ax1 + by1 + c) / a2 + b2
Solving, we get x = – 5 , y = 4
\therefore The required point is (– 5 , 4) .

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More