MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        Find the coefficient of x^99 in the expansion of (x+1)(x+2)(x+3)...(x+100).
10 months ago

Answers : (1)

Arun
15011 Points
							
Given polynomial:

(x + 1) (x + 2) (x + 3) . . . . . . (x + 100)

= x100 + (1 + 2 + 3 + . . . . . . . + 100) x99 + (. . .) x98 + . . . . . .

Here coeff. Of x99 = (1 + 2 + 3 + . . . . . . .+ 100)

= 100 x 101/2 = 5050.
 
 
Regards
Arun (askIITians forum expert)
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 233 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details