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`        Find the coefficient of x^99 in the expansion of (x+1)(x+2)(x+3)...(x+100).`
one year ago

Arun
23012 Points
```							Given polynomial:(x + 1) (x + 2) (x + 3) . . . . . . (x + 100)= x100 + (1 + 2 + 3 + . . . . . . . + 100) x99 + (. . .) x98 + . . . . . .Here coeff. Of x99 = (1 + 2 + 3 + . . . . . . .+ 100)= 100 x 101/2 = 5050.  RegardsArun (askIITians forum expert)
```
one year ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions