Grade 12th passAlgebra
Find the coefficient of x^99 in the expansion of (x+1)(x+2)(x+3)...(x+100).
1 Answer
Arun
Approved Tutor Answer8 Years agoGiven polynomial:
(x + 1) (x + 2) (x + 3) . . . . . . (x + 100)
= x100 + (1 + 2 + 3 + . . . . . . . + 100) x99 + (. . .) x98 + . . . . . .
Here coeff. Of x99 = (1 + 2 + 3 + . . . . . . .+ 100)
= 100 x 101/2 = 5050.
Regards
Arun (askIITians forum expert)
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