Algebra
Find number of permutation and combination of four letters taken away from the word EXAMINATION.
1 Answer
Sher Mohammad
A, I , N occurs twice
total distinct letters=8
selecting 4 letters all distinct=8C4=70
Selecting 2 same letters and 2 distinct =3C1*7C2=63
selecting 2same, 2same =3C2=3
total=136
and permutation, 8C4*4!+3C1*7C2*4!/2!+3C2*4!/2!2! = 24*70+63*12+3*6=2454
Sher Mohammad
B.Tech, IIT Delhi.
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algebra
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