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Find g'(x) if f(x)=|x-2| & g(x)=f[f(x)] for 2 less than or equal to x less than 4 A)1. B)-1. C)0. D) none of these
Find g'(x) if f(x)=|x-2| & g(x)=f[f(x)] for 2 less than or equal to x less than 4A)1.   B)-1.   C)0.    D) none of these


4 years ago

seetaram dantu
29 Points
							for 2  x  f(x) = x-2 now, g(x)= f[x-2] =f ([x] - 2)  we need to define piece wise  1) for 2  x x2) for 3  x  so g(x)=2 in case 1  and g(x)=1 in case 2  you can sustitute values of x for verification

4 years ago
seetaram dantu
29 Points
							keyboard errors:$case1 ==>, 2\leq x< 3$$, 2\leq x< 3$$case 1, 2\leq x< 3 =>g(x)= f(2-2)= f(0)= 2$  as step x is 2 in this case   case2==> $3\leq x< 4$  $g(x)= f(3-2)=f(1)=1$  as step x is 3 in this case sorry for the typing errors

4 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions