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Find g'(x) if f(x)=|x-2| & g(x)=f[f(x)] for 2 less than or equal to x less than 4 A)1. B)-1. C)0. D) none of these
for 2 x f(x) = x-2 now, g(x)= f[x-2] =f ([x] - 2) we need to define piece wise 1) for 2 x x2) for 3 x so g(x)=2 in case 1 and g(x)=1 in case 2 you can sustitute values of x for verification
keyboard errors: as step x is 2 in this case case2==> as step x is 3 in this case sorry for the typing errors
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