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`        find four members inGP whose sum is 85 and product is 4096`
one year ago

Arun
22615 Points
```							Dear Priya Let 4 numbers in GP are = a/r³, a/r, ar, ar³Nowa(1/r³ + 1/r + r + r³) = 85 And a⁴ = 4096a = 8Now you can find r,After that also youncan find 4 numbers. RegardsArun (askIITians forum expert)
```
one year ago
sahil
142 Points
```							let the term be x/r^3 ,x/r ,xr and xr^3now product =4096 =x/r^3×x/r×xr+xr^3=x^4 so x=4096^1/4=8now terms are 8/r^3+8/r+8r+8r^3sum =85 solve to get  r=2so terms are 8/2^3,8/2,8×2,8×2^3 lastly terms are 1,4,16,64If correct please give approval
```
one year ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions