Find for what value of 'a' equation x²+2ax-(a³-3a-3)=0 has real root

Question

Find for what value of 'a' equation x²+2ax-(a³-3a-3)=0 has real root ​

Prapul Muttineni · Answer

In the above eq for getting real values the discriminent shoul be greater than 0.So √(2a^2-4(1)(a^3-3a-3))>0 Please help me by approving So √4a^2+4a^3+12a+12>0 By factorisation√(a^2+3)(a+1)>0 So (a^2+3)(a+1)>0 please approve it and help me Thank you

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Find for what value of 'a' equation x²+2ax-(a³-3a-3)=0 has real root

Find for what value of 'a' equation x²+2ax-(a³-3a-3)=0 has real root

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Find for what value of 'a' equation x²+2ax-(a³-3a-3)=0 has real root ​

Find for what value of 'a' equation x²+2ax-(a³-3a-3)=0 has real root​

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Find for what value of 'a' equation x²+2ax-(a³-3a-3)=0 has real root

Find for what value of 'a' equation x²+2ax-(a³-3a-3)=0 has real root