Grade 10Algebra
find domain of y=sin^-1(2-3[x]/4)... plz explain properly
find domain of y=sin^-1(2-3[x]/4)... plz explain properly
1 Answer
Rajat
Approved Tutor Answer6 Years agosin -1 takes only values [-1,1]
So,
-1≤2-3[X]/4≤1
Or, -3≤-3[X]/4≤-1
Or, 4≥[X]≥(-4/3)
Thus, 4≥[X]≥(-1)
So, domain of X is [-1,4]
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