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# F(x)=x^2+pc+q a,b are roots then a^2 – b^2______________________________________________________________________________________________________________________________________________

3 years ago

manoj kumar
30 Points
For finding roots F(x)=0x^2+pc+q=0Root.    a= +(pc+q)^1/2              b= -(pc+q)^1/2 Then          a^2 = pc+q          b^2 = pc+q   Then       a^2- b^2 = pc+q-pc-q                     = 0

3 years ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions