Grade 12th passDifferential Calculus
f(x)+f(1-x)=2 , g(x)=f(x)-1 then g(x) is symmetrical about
f(x)+f(1-x)=2 , g(x)=f(x)-1 then g(x) is symmetrical about
2 Answers
Abhi singhal
f(x) + f(1-x) =2 and g(x)=f(X) – 1 then g(x) is symmetrical about 2 as we can see at 2 in graph there is a sharp edge and we know that at sharp edge the function is symmetrical
Vikas TU
Dear Student,
Given Function as:
g(x)= f(x)-1
g(x)= f(x)-1
So, f(x)= g(x)+1
So, g(x)+1 + g(1-x)+1= 2
Or, g(x) = - g(1-x)
Now , putting ½ - x in place of x
, g( ½-x) = - g( 1-1/2 + x)
= g( ½ + x)
Therefore this is symmetrical about the point (1/2,0)
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Thapar University)
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