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Evaluate using identities.. (99) 3 Please tell me easy way to do it Evaluate using identities..(99)3Please tell me easy way to do it
Dear Priya It is known that,(a+b)3=a3+b3+3ab(a+b)and(a−b)3=a3−b3−3ab(a−b)(i) (99)3 = (100 − 1)3= (100)3 − (1)3 − 3(100) (1) (100 − 1)= 1000000 − 1 − 300(99)= 1000000 − 1 − 29700= 970299
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