×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Evaluate using identities.. (99) 3 Please tell me easy way to do it
Evaluate using identities..(99)3Please tell me easy way to do it

```
2 years ago

Arun
25768 Points
```							Dear Priya It is known that,(a+b)3=a3+b3+3ab(a+b)and(a−b)3=a3−b3−3ab(a−b)(i) (99)3 = (100 − 1)3= (100)3 − (1)3 − 3(100) (1) (100 − 1)= 1000000 − 1 − 300(99)= 1000000 − 1 − 29700= 970299
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions