Equation of diameter of circie x2 + y2 -4x + 2y + √7 = 0 which passes through origin , is (1)2x+y=0 (2)x+2y=0 (3)x-2y=0 (4}

Question

ayush · Answer

Let the centre of circle be C(2,-1).Thus req. Eqn will be x+2y=0. Which will pass from both origin and centre.

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Equation of diameter of circie x2 + y2 -4x + 2y + √7 = 0 which passes through origin , is (1)2x+y=0 (2)x+2y=0 (3)x-2y=0 (4}

Equation of diameter of circie x2 + y2 -4x + 2y + √7 = 0 which passes through origin , is (1)2x+y=0 (2)x+2y=0 (3)x-2y=0 (4}

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Equation of diameter of circie x2 + y2 -4x + 2y + √7 = 0 which passes through origin , is (1)2x+y=0 (2)x+2y=0 (3)x-2y=0 (4}

Equation of diameter of circie x2 + y2 -4x + 2y + √7 = 0 which passes through origin , is (1)2x+y=0 (2)x+2y=0 (3)x-2y=0 (4}

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