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Equation of circle whose radius is 4 unit, centre is on x-axis and passes through origin--Explain????

Nitin Kumar , 8 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Let the centre be (a,0)
then from the distance formulae we get,
root(a^2 +0^2) = 4
or
a^2 = 16
a = +4 or -4
Hence, eqn. of circle,
(x-4)^2 + y^2 = 16

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