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`        Equation of circle whose radius is 4 unit, centre is on x-axis and passes through origin--Explain????`
3 years ago

Vikas TU
10603 Points
```							Let the centre be (a,0)then from the distance formulae we get,root(a^2 +0^2) = 4ora^2 = 16a = +4 or -4Hence, eqn. of circle,(x-4)^2 + y^2 = 16
```
3 years ago
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions