Grade 12th passAlgebra
eqn 3x2+px+3=0, p>0 and one roots of equation is the square of the other find the value of p
eqn 3x2+px+3=0, p>0 and one roots of equation is the square of the other find the value of p
1 Answer
Arun
Dear student
let root is a and a^2
a + a^2 = – p/3
a^3 = 1
hence
a = 1
p = -6
hope it helps
Regards
Arun
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