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Eight times the first of three consecutive odd integers is 4 less than thrice the sum of second and third. The second integer is ___
Dear student Let, the three consecutive odd integers be (x+1) , (x+3) , (x+5) So,Eight times the first number = 8(x+1)Sum of second and third number = (x+3) + (x+5) According to Sum, 8 ( x + 1 ) + 4 = 3 [( x + 3 ) + ( x + 5 )]↬8x + 8 + 4 = 3 [ x + 3 + x + 5 ]↬ 8x + 12 = 3 ( 2x + 8)↬ 8x + 12 = 6x + 24↬ 8x - 6x = 24 - 12↬ 2x = 12↬ x = 6 Second number =⇢ ( x + 3 )⇢ ( 6 + 3 )⇢ 9
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