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# Distance between two parallel planes 2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0 is (1) 5/2(2) 7/2 (3) 9/2(4) 3/2

SHAIK AASIF AHAMED
6 years ago
Hello student,
Given planes are2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0
multiplying 1stequation by 2 we get
4x+2y+4z=16 and 4x+2y+4z=-5
distance between the planes=16-(-5)/sqrt(42+22+42)
=21/6=7/2
Thanks and Regards
Shaik Aasif
|c1-c2|\$\sqrt{a2=b2=c2}$simple firstly make x,y,z cofficient of both planes equation in same ratio thansolve easily thank u regard ankit singh