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Distance between two parallel planes 2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0 is (1) 5/2 (2) 7/2 (3) 9/2 (4) 3/2

aditya kashyap , 12 Years ago
Grade upto college level
anser 2 Answers
SHAIK AASIF AHAMED
Hello student,
Given planes are2x + y + 2z = 8 and 4x + 2y + 4z + 5 = 0
multiplying 1stequation by 2 we get
4x+2y+4z=16 and 4x+2y+4z=-5
distance between the planes=16-(-5)/sqrt(42+22+42)
=21/6=7/2
Thanks and Regards
Shaik Aasif
askIITians faculty
Last Activity: 11 Years ago
ankit singh
|c1-c2|\\sqrt{a2=b2=c2}simple firstly make x,y,z cofficient of both planes equation in same ratio thansolve easily thank u regard ankit singh
Last Activity: 5 Years ago
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