Arun
Last Activity: 5 Years ago
firstly in such questions try to find pattern between numbers : here it is 2n2 and then try to express it in form of tan-1a – tan-1b
∑ cot-1 ( 2n2 ) = ∑ tan-1 ( 1/2n2 ) { from n=1 to infinity }
tan-1 ( 2/4n2 ) = tan-1 { (2n+1) – (2n - 1) \1 + (2n - 1)(2n+1) } …......................1
tan-1a - tan-1b = tan-1 {(a-b)/1 + a*b}
so equation 1 equals to tan-1 (2n+1) – tan-1 (2n-1)
so now the qauestion is ∑ {tan-1 (2n+1) – tan-1 (2n-1) } [ n from 1 to infinity]
so now the answer is (
/2 –
/4 ) =
/4
Regards
Arun