Rajat
Last Activity: 5 Years ago
Number of subsets of X = 22=4
Which are

, {1}, {2}, {1,2}
Say Y=

Then Z can be {1},{2},{1,2}
Thus we get 3 ordered pairs
Similarly 3 more when Z=

In total 6 when either Y or Z is phi.
Now let the cases when none of them is phi.
None of them can be {1,2} since intersection is null.
Therefore only two possibilities of (X,Y)
= ({1},{2}) or ({2},{1})
In total we can have 3+3+2= 8 ordered pairs
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