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        Consider X ={1,2 }. The number of different ordered pairs(Y,Z) that can be formed such that Y and Z are subsets of X and Y intersection Z is empty, is?..Please, solve this manually, means i need those subsets and ordered pairs..
one year ago

Rajat
213 Points
							Number of subsets of X = 22=4Which are $\phi$, {1}, {2}, {1,2}Say Y= $\phi$Then Z can be {1},{2},{1,2}Thus we get 3 ordered pairsSimilarly 3 more when Z= $\phi$In total 6 when either Y or Z is phi.Now let the cases when none of them is phi.None of them can be {1,2} since intersection is null.Therefore only two possibilities of (X,Y)= ({1},{2}) or ({2},{1})In total we can have 3+3+2= 8 ordered pairs Kindly upvote!

one year ago
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