Grade 12Algebra

Calculate as x approaches -8(+)(right hand limit) of 2x/x+8.

Abhishek

12 Years agoGrade 12

2 Answers

Jitender Singh

12 Years ago

Ans:

$L = \lim_{x\rightarrow -8^{+}}\frac{2x}{x+8}$

$-8\rightarrow -8+h, h>0$

$L = \lim_{h\rightarrow 0}\frac{2(-8+h)}{-8+h+8}$

$L = \lim_{h\rightarrow 0}\frac{-16+2h}{h} = +\infty$

Thanks & Regards

Jitender Singh

IIT Delhi

askIITians Faculty

Jitender Singh

12 Years ago

Sorry about the previous answers, there is an minor mistake.

L = (-ve) Infinity

Thanks & Regards

Jitender Singh

IIT Delhi

askIITians Faculty

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Calculate as x approaches -8(+)(right hand limit) of 2x/x+8.

Abhishek

2 Answers

Jitender Singh

Jitender Singh

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