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        C0 +C1x +C2x2 + ----------------+Cnxn  then prove that C12 +2C22 +3C32 + -------------+nCn2 = (2n-1)/[(n-1)!]2
3 years ago

moumi roy
91 Points
							$(1+x)^{n}=C_{0}+C_{1}x...C_{1}x^{n}\Rightarrow differentiating w.r.t x\Rightarrow n(1+x)^{n-1}=c_{1}+2c_{2}x+....nc_{n}x^{n-1}\Rightarrow multiplying with (1+x)^{n} \Rightarrow (1+x)^{2n-1}n=(c_{1}+2c_{2}x+....nc_{n}x^{n-1})(C_{0}+C_{1}x...C_{1}x^{n} )\Rightarrow coiff of \mathbf{x^{n-1}} in\mathbf{n (1+x)^{2n-1}}\Rightarrow n*_{n-1}^{2n-1}\textrm{C}$HERE C0=CN &C1=CN-1 FORM IS USED CALCULTING WILL FETCH U THE RESULT.THINK THIS THE ANSWER ONLY.NOT ACCEPTINF LESS THAN 100

3 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions