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Based on remainder theorem..zeroes of biquadratic equation are gievn..please help with atleast few steps Based on remainder theorem..zeroes of biquadratic equation are gievn..please help with atleast few steps
dear student, biquadratic polynomial means it has degree 4.also, since its roots are given to be – 2, 3, 5, 7, it means that we can factorise f(x) as follows:f(x)= A(x – ( – 2))(x – 3)(x – 5)(x – 7)= A(x+2)(x – 3)(x – 5)(x – 7), where A is the leading coefficient.put x=0 both sidesf(0)= A(2)(-3)(-5)(-7)or A= – 1/210, since f(0)= 1so, the remainder when f(x) is divided by x – 1, would be f(1) (using remainder theorem)so, f(1)= A(1+2)(1 – 3)(1 – 5)(1 – 7)= – (1/210)(3)(-2)(-4)(-6)= 24/35option CKINDLY APPROVE :))
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