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Grade Upto college levelAlgebra

Area bounded by the curve y=sin x between x=0 & x=360 is

Profile image of Srijan
12 Years agoGrade Upto college level
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2 Answers

Profile image of SHAIK AASIF AHAMED
12 Years ago
Hello student,
Area bounded by sinx in (0,360) is given by
\int_{0}^{2\pi }sinx=
2\int_{0}^{\pi }sinx=2(-cosx) in the limits (0,\pi )=-2(-2)=4
Hence the area is 4 sq.units
Thanks and regards
Shaik Aasif
askIITians faculty
Profile image of SHAIK AASIF AHAMED
12 Years ago
Hello student,
Area bounded by sinx in (0,360) is given by
\int_{0}^{2\pi }sinx=
2\int_{0}^{\pi }sinx=2(-cosx) in the limits (0,\pi )=-2(-2)=4
Hence the area is 4 sq.units
Thanks and regards
Shaik Aasif
askIITians faculty