Grade 12th passAlgebra
Ap gp hp problem from nda paper .please give satisfy solution for this question
1 Answer
jayant rathi
x,y,z are in AP so 3y=15,gives y=5,
now y is the arithmetic mean of a and b also so a+b=10
now likewise 1/p,1/q and 1/r are in ap so 3/q=5/3,q=9/5;
now 1/a+1/b=2/q, so (a+b)/ab=10/9;
so ab=9,now using simple logic if ab=9,and a+b=10, the a=1 and b=9 are the only possibility;
so the ap comes out to be 1,3,5,7,9 so xyz=105;
and hp comes out to be 1,9/7,9/5,3,9 so pqr=243/35
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