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anyone who answers this question please explain in detail the question is given in the attachment

anyone who answers this question
please explain in detail 
the question is given in the attachment

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Grade:12

1 Answers

Pavan Kumar
32 Points
6 years ago
Dear student,x^2+1>0 is true for all x because x^2>=0, so the solution of this is -infinity to +infinityThe question means that the solution of x in the second equation should be the same as the first equationSo case 1:a-1>0 The equation becomes (a-1)x^2+(2a+1)x+1>=0 this means for every value of a the function should be greater than or equal to 0.As this is a quadratic equation and (a-1)>0 the graph is upwardIf the minimum value of quadratic equation is greater than or equal to 0 the the whole fu action is obviously greater than or equal to 0 Minimum value = -D/4(a-1) D is discriminantD=(2a+1)^2-4(a-1)*1=4a^2+2-D/4(a-1)=-(4a^2+2)/4(a-1)>=0 (4a^2+2)/4(a-1)=0Graph is downward so the graph obviously goes to - infinity so in this case also no solution 0 solutions THANK YOU 1 is violated Case 2: a-1

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