Rajat
Last Activity: 5 Years ago
Sum of series= 3(12)/3+ 6(12+22)/5 +
9(12+22+32)/7 +.....
Tk= 3k(12+22+...k^2)/(2k+1)
= 3k(2k+1)(k)(k+1)/6(2k+1)
= k^2(k+1)/2 =1/2(k^3+k^2)
Sum of series = 1/2{(12+22....+k^2) +(13+23...+k^3)}
=1/2{(2k+1)(k)(k+1)/6 + (k(k+1)/2)^2}
=1/2{(31×15×16/6)+(15×16/2)2}
= 7820