0

Guest

Courses New

An urn contains 2 white and 2 black balls. A ball is drawn at random. If it is white, it is not replaced into the urn. Otherwise, it is replaced with another ball of the same colour. The process is repeated. Find the probability that the third ball drawn is black.

An urn contains 2 white and 2 black balls. A ball is drawn at random. If it is white, it is not replaced into the urn. Otherwise, it is replaced with another ball of the same colour. The process is repeated. Find the probability that the third  ball drawn is black.

Grade:12

1 Answers

denesh
23 Points
9 years ago
3/4-(case 1:(1/2*1/3*1+1/2*2/3*3/4) + case 2:(1/2*2/5*2/3+1/2*3/5*2/3))
This has to be solved by taking cases..
Case 1 is drawing a white in first attempt and 2 is for drawing a black (it is one in the 3rd term of case 1 first expression bcz by then all white balls would have gone and so on for the next sub cases that arise..

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More