SHAIK AASIF AHAMED
Last Activity: 10 Years ago
let the length of square to be cut is x metres
volume of the box can be represented as
V=(x)(5-2x)(7-2x)......................(1)
V=4x3-24x2+35x
to find maximum volume differentiate V and make it equal to zero
V1=12x2-48x+35=0
we get x=23/24
by substituting x=23/24 in (1) we get
Volume of largest box V=15 m3