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`        An ellipse having foci at (3,3) &(-4,4) &passing through the origin has eccentricity equql to`
5 months ago

Arun
23386 Points
```							Since origin in on the elipse therefore assum P(0,0) on elipse,Let S1 = (3,3) and S2 = (-4,4)Since we know that, PS1 + PS2 =2aor2a = 7root(2) – --(1)also S1S2 = 2aeor 2ae = 5 root(2) --- (2)Divide (2) by (1) and get e = 5/7
```
5 months ago
Vikas TU
9810 Points
```							Dear student P(3,3)Q(-4,4)O(0,0)e = PQ/(OP+OQ)e = sqrt[(3-4)^2 + (3+4)^2] / sqrt(9+9) + sqrt(16+16)e = sqrt 50 / 7root 2= 5 root 2 / 7 root 2 = 5/7
```
5 months ago
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