An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.

Dear Student

From the question,
The initial height of the elevator = 10 m
Final depth of elevator = -350 m ... [∵distance descended is denoted by a negative
integer]
The total distance to descended by the elevator = (-350)–(10)
= - 360 m
Then,
Time taken by the elevator to descend -6 m = 1 min
So, time taken by the elevator to descend–360 m
= (-360) ÷ (-60)
= 60 minutes
= 1 hour

Thanks