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`        alpha and beta are roots of ax2+bx+c then the equation ax2-bx(x-1)+c(x-1)2 has roots?`
11 months ago

1673 Points
```							ax2-bx(x-1)+c(x-1)2=0divide by (x-1)^2a(x/(x-1))^2-bx/(x-1)+c=0now set x/(x-1)= – yso eqn becomesay^2+by+c=0roots of this eqn are obviously alpha and betasince  x/(x-1)= – ytherefore x= y/(y+1)so roots of ax2-bx(x-1)+c(x-1)2=0 are alpha/(alpha+1) and beta/(beta+1)
```
11 months ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions