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Grade 10Algebra

abcd is trapezium with AB parallel to CD, F is the midpoint of BC, DF and AB are produced to E, meet at E. Show that F is also the mid point of DE.

Profile image of Madhan
8 Years agoGrade 10
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1 Answer

Profile image of Vedavyas
8 Years ago
Triangle BFE and CFD is condruent by ASA Congruency theorem. Therefore DF =FE hence F is the mid point of DE.

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