ABCD is a trapezium with ab parallel to CD and th

Question

ABCD is a trapezium with ab parallel to CD and the diagonals intersect at a point P the area of triangle ABP is 32 CM square and the area of triangle sea DP is 50 cm square the area of trapezium is

Arun · Accepted Answer

The area of Trapezium = 1/2(AB+CD).H

Let AB = 4x & CD = 5x (since you already found that sides are in 4:5)

Let the heights be h1 & h2 respectively.

Then H = h1 + h2

Area = 1/2 * (4x+5x)(h1+h2)
= 1/2 * 9x * h1 + 1/2 * 9x * h2

1/2 * 4x*h1 = 32
1/2 * 9x*h1 = 32 * 9/4 = 72

1/2 * 5x * h2 = 50
1/2 * 9x * h2 = 50 * 9/5 = 90

Area = 72 + 90 = 162

Algebra> ABCD is a trapezium with ab parallel to C...

ABCD is a trapezium with ab parallel to CD and the diagonals intersect at a point P the area of triangle ABP is 32 CM square and the area of triangle sea DP is 50 cm square the area of trapezium is

Rohit , 6 Years ago

Arun

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Algebra> ABCD is a trapezium with ab parallel to C...

ABCD is a trapezium with ab parallel to CD and the diagonals intersect at a point P the area of triangle ABP is 32 CM square and the area of triangle sea DP is 50 cm square the area of trapezium is

Rohit , 6 Years ago

Arun

LIVE ONLINE CLASSES

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