Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A vehicle moving with velocity, Vo on a rough horizontal road is brought to rest in a distance, s. If the coefficient of static friction between the tyres is µ, show that it is independent of the mass of the vehicle. Hence calculate s, when µ = 0.5 and V0 = 90 kmh-1. [g =10 ms-2]

A vehicle moving with velocity, Vo on a rough horizontal road is brought to rest in a distance, s. If the coefficient of static friction between the tyres is µ, show that it is independent of the mass of the vehicle. Hence calculate s, when µ = 0.5 and V0 = 90 kmh-1.  [g =10 ms-2]

Grade:12th pass

1 Answers

Ram Kushwah
108 Points
one month ago
Here u = V,v=0  Distantance=s
So  v²= u²+2as
 
0= V0²  + 2as
a  =  – V0²  / 2s
Thus force  between tyres and road
F = ma = – mV0²  /  2s …..................(1)
 Now  force due to friction 
F= – μmg..........................................(2)
From(1) and (2)
 
– mV0²  /  2s = – μmg.
2sμg. = V0² 
s = V0² / μg 
Hence distance s is independent of  mass m
Putting all the given values we get
s=(90*1000/3600)²/0.5*10   ( as 1 km/h=1000/3600 m/s)
=625/5
=125 m
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free