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A straight line through the origin meet The parallel line 4 x + 2 y = 9 and 2 X + Y + 6 = 20 at the point P and Q respectively then the point O divides the segment PQ in the ratio
The given parallel lines are 4x + 2y = 9 and 2x + y + 6 = 0.The distance of the origin from 4x + 2y – 9 = 0 is |-9|/√42 + 22 = 9/√20.Similarly, the distance of origin from 2x+ y + 6 = 0 is |6|/√22 + 12 = 6/√5.Hence, the required ratio is (9/√20) / (6/√5) = ¾.
The given parallel lines are 4x + 2y = 9 and 2x + y + 6 = 0.
The distance of the origin from 4x + 2y – 9 = 0 is |-9|/√42 + 22 = 9/√20.
Similarly, the distance of origin from 2x+ y + 6 = 0 is
|6|/√22 + 12 = 6/√5.
Hence, the required ratio is (9/√20) / (6/√5) = ¾.
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