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`        A set contains (2n+1) elements.If the number of subsets of this set which contains almost n elements is 4096,then the value of n is`
one year ago

Arun
22540 Points
```							Take the power set. It has 2^(2n+1) members.Replace any member which has n+1 or more elements by its complements.Now the power set has members, which has n or fewer elements, and each such such member appears twice.Therefore, when multiplicity is removed, you get 2^(2n+1)/2 members, which is 2^(2n). Hence2^2n = 40962^2n = 2^122n = 12n = 6 RegardsArun (askIITians forum expert)
```
one year ago
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