A sequence has nth term given by Tn=(n2+1)n!. Find summation (sigma) Tn.
A sequence has nth term given by Tn=(n2+1)n!. Find summation (sigma) Tn.
User , 5 Years ago
Grade 12th pass
IIT JEE Entrance Exam> A sequence has nth term given by T n =(n ...
1 Answersbasil mansuri
Since according to your question the Nth term is i.e. Tn= (n^2+1)n.
Apply the special series and sequence formula you will get your answer.
Tn = (n^2+1)n = n^3+n
Sn= sigma(k=1 to k = n) k^3+ sigma(k=1 to k=n) k
Sn= [ n(n+1)/2)]^2 + n(n+1)/2
Sn= n(n+1)/2 * [n(n+1)/2 + 2]
Sn= n(n+1)(n^2+n+2)/4
Hence thats your answer. Thank you very much.
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