bharat bajaj
Last Activity: 11 Years ago
There is some correction in question. The rectangle cant have any minimum area. We will find out the maximum area.Let the triangle be ABC with BC on the x axis and point A on y axis.A(0,h) B(-1/2,0) C(1/2,0)Say the rectangle be EFGH with EF side on side BC.E(-x,0) F(x,0) G(x,y) H(-x,y)Now the points A G and C lie on same line. Hence, from slope-2h = y/(x-1/2)y = h - 2hxNow the area of rectangle A = 2xy = 2xh(1-2x)Differentiate it : 2h( 1 - 4x) = 0Hence, x = 1/4, y = h/2
These are the conditions for the maximum area by rectangle. The question is incomplete. Hence, these are the final answers.
Thanks
Bharat Bajaj
IIT Delhi
askiitians faculty
