A ray of light along x+(3y)^1/2 =3 gets reflected upon reaching x-axis, the equation of the reflected rays is

Question

Jitender Singh · Answer

Ans:
Hello Student,
Please find answer to your question below

Equation of ray of light:
$x + \sqrt{3}y = 3$
$\sqrt{3}y = -x + 3$
$y = -\frac{1}{\sqrt{3}}x + \sqrt{3}$
This line make 150 degree with +ve x – axis.
So this makes 60 degree with normal.
So reflected light make 30 degree with +ve x – axis.
Equation of reflected light:
$(y - \sqrt{3}) = \frac{1}{\sqrt{3}}(x - 0)$
$y = \frac{x}{\sqrt{3}} + 3$

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A ray of light along x+(3y)^1/2 =3 gets reflected upon reaching x-axis, the equation of the reflected rays is

A ray of light along x+(3y)^1/2 =3 gets reflected upon reaching x-axis, the equation of the reflected rays is

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A ray of light along x+(3y)^1/2 =3 gets reflected upon reaching x-axis, the equation of the reflected rays is

A ray of light along x+(3y)^1/2 =3 gets reflected upon reaching x-axis, the equation of the reflected rays is

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