Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A point moves in x-y plane such that the sum of its distances from two mutually perpendicular lines is always equal to 2^(1/2) units. The area encloced by the locus of the point is (in sq. units)

A point moves in x-y plane such that the sum of its distances from two mutually perpendicular lines is always equal to 2^(1/2) units. The area encloced by the locus of the point is (in sq. units)

Grade:12th pass

2 Answers

bharat bajaj IIT Delhi
askIITians Faculty 122 Points
7 years ago
Say the mutually perpendicular lines are x and y axis :
Hence, the locus of point is : x+y = v2
Hence, it is a line.
Area enclosed by the line and both axes :
1/2 . v2. v2. = 1 unit sq.
Thanks
Bharat Bajaj
IIT Delhi
askiitians faculty
Daksh Kumar
26 Points
4 years ago
The Lines Will Be X+y=√2 , x-y=√2-X-y=√2 , y-x=√2 and They line no. 1&4 will make a intercept of √2 units on X-axis hence length of diagonal of square will be 2√2 And Hence Side Will be 2 units So area of square= Sidexside Hence Ans. = 2x2 = 4

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free