A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45° with the initial vertical direction is ?

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SHAIK AASIF AHAMED · Answer

Hello student, From the given data we can write the equation as F l sin 45 = Mg (l&minus; lcos 45) F = Mg (&radic;2 &minus; 1) Thanks and Regards Shaik Aasif askIITians faculty

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A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45° with the initial vertical direction is ?

A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45° with the initial vertical direction is ?

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A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45° with the initial vertical direction is ?

A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45° with the initial vertical direction is ?

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

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Answer and earn gift vouchers

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