A man 160 cm tall walks away from a source of light situated at the top of the pole 6m high at the rate of 1.1 m/sec. How fast is the length of the shadow increasing when he is 1m away from the pole.

Question

SHAIK AASIF AHAMED · Answer

Hello student,
Please find the answer to your question below
From the given dataA man 160 cm tall walks away from a source of light situated at the top of the pole 6m high at the rate of 1.1 m/sec.
So x²+y²=100²+440²
by differentiating we get
dy/dt=(-x/y)dx/dt
by substituting the values we get
dy/dt=0.4cm/s

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A man 160 cm tall walks away from a source of light situated at the top of the pole 6m high at the rate of 1.1 m/sec. How fast is the length of the shadow increasing when he is 1m away from the pole.

A man 160 cm tall walks away from a source of light situated at the top of the pole 6m high at the rate of 1.1 m/sec. How fast is the length of the shadow increasing when he is 1m away from the pole.

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A man 160 cm tall walks away from a source of light situated at the top of the pole 6m high at the rate of 1.1 m/sec. How fast is the length of the shadow increasing when he is 1m away from the pole.

A man 160 cm tall walks away from a source of light situated at the top of the pole 6m high at the rate of 1.1 m/sec. How fast is the length of the shadow increasing when he is 1m away from the pole.

1 Answers

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