A man 160 cm tall walks away from a source of light situated at the top of the pole 6m high at the rate of 1.1 m/sec. How fast is the length of the shadow increasing when he is 1m away from the pole.

Hello student,
Please find the answer to your question below
From the given data
A man 160 cm tall walks away from a source of light situated at the top of the pole 6m high at the rate of 1.1 m/sec.
So x²+y²=100²+440² by differentiating
we get dy/dt=(-x/y)dx/dt by substituting the values we get dy/dt=0.4cm/s