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A line is such that its segment between the lines 5x-y+4=0 and 3x+4y-4=0 is bisected at the point (1,5). Obtain its equation?

A line is such that its segment between the lines 5x-y+4=0 and 3x+4y-4=0 is bisected at the point (1,5). Obtain its equation?

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1 Answers

ng29
1698 Points
8 years ago
consider arbitrary point on both lines
(a,4-3a/4)
(b-4/5,b)
(1,5) is mid point of these points on finding a and b we get eq of line as these points lie on required line
 
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