A company manufactures two types of sweaters, type A and type B. It costs Rs. 360
to make one unit of type A and Rs. 120 to make a unit of type B. The company can
make atmost 300 sweaters and can spend atmost Rs. 72000 a day. The number of
sweaters of type A cannot exceed the number of type B by more than 100. The
company makes a profit of Rs. 200 on each unit of type A but considering the difficulties of a common man the company charges a nominal profit of Rs. 20 on a
unit of type B. Using LPP, solve the problem for maximum profit.

Question

SHAIK AASIF AHAMED · Answer

Hello student,

let the company manufactures sweaters of type A = x, and that of type B = y. daily
LPP is to Maximise P = 200x + 20y
such that x+y $\leq$ 300
360 x + 120y $\leq$ 72000
x – y $\leq$ 100
x $\geq$ 0 y $\geq$ 0

Getting vertices of the feasible region as
A (100, 0), B (175, 75), C (150, 150) and D (0, 300)
Maximum profit at B
So Maximum Profit = 200 (175) + 20 (75)
= 35000 + 1500
= Rs. 36500

Thanks and Regards

Shaik Aasif

askIITians faculty

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Algebra

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship