A COIN IS TOSSED 6 TIMES .FIND THE NO OF GETTING 4 HEADS AND 2 TAILS
Zia Ullah
9 Years agoGrade 11
1 Answer
Arnab Roy
9 Years ago
Use Binomial Theorem nCr (p)^r (q)^n-r probability of getting a head is 1/2=p probability of NOT getting a head is 1/2=q n=6 r=2 6C2 *(1/2)^2 * (1/2)^6-2 = 6C2*(1/2)^6 =15/64