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A circle passes through the point (-1,3)&(5,11)and radias is 5 .then its centre is

Amit Verma , 7 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Let the center is (h,k)
=> (h+1)2 + (k-3)2 = (h-5)2 +(k-11)2 =52
=> (h+1)2 + (k-3)2 = (h-5)2 +(k-11)2
simplify
3h +4k=34 ...............1
 
(h+1)2 + (k-3)2 =52
h2 +k2 +2h -6k  =15 ..............2
 
Solving equation 1 and equation 2 we get,
h2 + ((34 – 3h)/4)2 +2h – 3(34 – 3h)/2  =15
On solving frther we get,
h = 5 and k = -3
 

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