A bomb of 18kg explodes into 12 kg and 6 kg the velocity of 12 kg is 5 m/s the KE of the other piece

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Mahima Kanawat · Answer

Dear student ....By momentum conservation , mv=m1v1+m2v2 , 18×0=12×5+6×v2 , on solving v2= 10 m/s. Therefore , KE =1/2mv²=1/2×6×100=300 J.....With Regards....Mahima....(AskIITians Forum Expert )

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A bomb of 18kg explodes into 12 kg and 6 kg the velocity of 12 kg is 5 m/s the KE of the other piece

A bomb of 18kg explodes into 12 kg and 6 kg the velocity of 12 kg is 5 m/s the KE of the other piece

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A bomb of 18kg explodes into 12 kg and 6 kg the velocity of 12 kg is 5 m/s the KE of the other piece

A bomb of 18kg explodes into 12 kg and 6 kg the velocity of 12 kg is 5 m/s the KE of the other piece

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